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Question

Chemistry Question on Structure of atom

The de Broglie wavelength of a particle with mass 1 kg and velocity 100 m/s is

A

6.6×10−33 m{ 6.6 \times 10^{-33} \, m}

B

6.6×10−36 m{ 6.6 \times 10^{-36} \, m}

C

3.3×1033 m{ 3.3 \times 10^{33} \, m}

D

3.3×10−36 m{ 3.3 \times 10^{-36} \, m}

Answer

6.6×10−36 m{ 6.6 \times 10^{-36} \, m}

Explanation

Solution

de Broglie equation
λ=hmv=6.62×10−34 kg m2 s−11kg×100 m s−1{\lambda = \frac{h}{mv} =\frac{6.62 \times10^{-34}\, kg \,m^{2} \, s^{-1}}{1 kg \times100 \, m \, s^{-1}}}
=6.62×10−36 m{ = 6.62 \times 10^{-36} \, m}