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Question: The de-Broglie wavelength of a particle with mass \(1gm\) and velocity \(100m/\sec\) is...

The de-Broglie wavelength of a particle with mass 1gm1gm and velocity 100m/sec⁡100m/\sec is

A

6.63×10−33m6.63 \times 10^{- 33}m

B

6.63×10−34m6.63 \times 10^{- 34}m

C

6.63×10−35m6.63 \times 10^{- 35}m

D

6.65×10−35m6.65 \times 10^{- 35}m

Answer

6.63×10−33m6.63 \times 10^{- 33}m

Explanation

Solution

λ=hmv=6.63×10−3410−3×100=6.63×10−33m\lambda = \frac{h}{mv} = \frac{6.63 \times 10^{- 34}}{10^{- 3} \times 100} = 6.63 \times 10^{- 33}m