Question

The de Broglie wavelength of a particle of kinetic energy K is $\lambda.$ What will be the wavelength of the particle , If its kinetic energy is $\frac{K}{4}$:

• A. $\lambda$
• B. $2\lambda$
• C. $\frac{\lambda}{2}$
• D. $4\lambda$

Answer 1

Answer: (B)

$2\lambda$

Answer 2

: de Broglie wavelength,

$\lambda = \frac{h}{\sqrt{2mk}}$…. (i)

When the kinetic energy is $\frac{k}{4}$ then

$\lambda' = \frac{h}{\sqrt{2m(k/4)}} = \frac{2h}{\sqrt{2mk}} = 2\lambda(u\sin g(i))$