Question

The de-Broglie wavelength of a particle moving with a velocity 2.25 × 10⁸ m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is : (velocity of light is 3 × 10⁸ m/s)

• A. 1/8
• B. 3/8
• C. 5/8
• D. 7/8

Answer 1

Answer: (B)

3/8

Answer 2

$\frac{K.E_{e}}{K.E_{Ph}}$ = $\frac{v}{2c}$ = $\frac{2.25 \times 10^{8}}{2 \times 3 \times 10^{8}}$ = $\frac{3}{8}$