Solveeit Logo
Login

Question

Question: The de-Broglie wavelength of a particle moving with a velocity 2.25 × 10<sup>8</sup> m/s is equal to...

The de-Broglie wavelength of a particle moving with a velocity 2.25 × 108 m/s is equal to the wavelength of a photon. The ratio of effective mass of photon to the particle is- (Given : velocity of light is 3 × 108 m/s)

A

1/8

B

¾

C

5/8

D

7/8

Answer

¾

Explanation

Solution

lp = lph ̃ pp = pph ̃ mpvp = mphvph

̃ mpmph\frac{m_{p}}{m_{ph}} = vphvp\frac{v_{ph}}{v_{p}} = 32.25\frac{3}{2.25} = 43\frac{4}{3}

mphmp\frac{m_{ph}}{m_{p}} = 34\frac{3}{4}