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Question

Question: The de-Broglie wavelength l of a particle with mass m and kinetic energy E is given by –...

The de-Broglie wavelength l of a particle with mass m and kinetic energy E is given by –

A

λ=h2mE\lambda = h\sqrt{2mE}

B

λ=2mEh\lambda = \frac{\sqrt{2mE}}{h}

C

λ=h2mE\lambda = \frac{h}{\sqrt{2mE}}

D

λ=hE2mE\lambda = \frac{hE}{\sqrt{2mE}}

Answer

λ=h2mE\lambda = h\sqrt{2mE}

Explanation

Solution

λ=hP=h2m(k.a.)\lambda = \frac{h}{P} = \frac{h}{\sqrt{2m(k.a.)}}