The de Broglie wavelength is proportional to | PHYSICS - DE BROGLIE'S EXPLANATION OF BOHR'S SECOND POSTULATE OF QUANTISATION | SolveeIt | Solveeit

Today, August 19

Question

The de Broglie wavelength is proportional to

A

lµ $\frac{1}{v}$

B

l µ $\frac{1}{m}$

C

l µ $\frac{1}{p}$

D

l µ p

Answer

l µ $\frac{1}{p}$

Explanation

Solution

l = $\frac{h}{p}$

l µ $\frac{1}{p}$