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Question

Question: The de-Broglie wavelength is proportional to....

The de-Broglie wavelength is proportional to.

A

λ∝1ν\lambda \propto \frac{1}{\nu}

B

λ∝1m\lambda \propto \frac{1}{m}

C

λ∝1p\lambda \propto \frac{1}{p}

D

λ∝p\lambda \propto p

Answer

λ∝1p\lambda \propto \frac{1}{p}

Explanation

Solution

λ=hp⇒λ∝1p\lambda = \frac{h}{p} \Rightarrow \lambda \propto \frac{1}{p}