Question

The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is

• A. $0.3 A˚$
• B. $3.3 A˚$
• C. $6.26 A˚$
• D. $10 A˚$

Answer 1

Answer: (B)

$3.3 A˚$

Answer 2

De-Broglie wavelength is given by
$\lambda=12.27 / \sqrt{ E }_{0}$,
where $E _{0}$ is the ground state energy of the hydrogen atom
whose value is $13.6\, V$
$\therefore \lambda=12.27 /(\sqrt{1} 3.6)=3.33 \,?$