Question

The de Broglie wavelength associated with an electron having a kinetic energy of 10 eV is –

• A. 10 Å
• B. 12.27 Å
• C. 3.9 Å
• D. 0.10 Å

Answer 1

Answer: (C)

3.9 Å

Answer 2

l_e =$\frac{12.27}{\sqrt{K.E.(eV)}}$ Å = $\frac{12.27}{\sqrt{10}}$Å