Chemistry Question on Electronic Configurations Of Elements And The Periodic Table

Question

The d-electronic configuration of $\left[ CoCl _4\right]^{2-}$ in tetrahedral crystal field is $e ^{ m } t _2 ^n$ Sum of " $m$ " and "number of unpaired electrons" is

Accepted Answer

The correct answer is 7.
The d-electronic configuration of CoCl 42- in tetrahedral crystal field is e m t 2 n Sum of "m" and "number of unpaired electrons" is

Co2+:3d74s0,Cl−:WFL
Configuration e4t23:m=4
Number of unpaired electrons =3
So, answer =7