Question

The cycle is shown in figure is followed by an engine made of one mole of perfect gas in a cylinder with a piston. The processes A to B and C to D are isochoric whereas process B to C and D to A are adiabatic, the work done by the engine in one cycle is

(VA = VB = V, VC = VD = 2V and g = 5/3)

• A. [1 – 43/2](PB – PA)V
• B. $\frac { 3 } { 2 }$ [1 – 32/3](PB – PA)V
• C. $\frac { 3 } { 2 }$ [1 – 2–2/3](PB – PA)V
• D. $\frac { 5 } { 2 }$ [1 – 2–2/3](PB – PA)V

Answer 1

Answer: (C)

$\frac { 3 } { 2 }$ $1 – 2–2/3$(PB – PA)V

Answer 2

: $\frac { 3 } { 2 } \left[ 1 - 2 ^ { - 2 / 3 } \right] \left( P _ { B } - P _ { A } \right) V$