Question

The cut-off voltage of the diodes (shown in figure) in forward bias is $0.6\; V$. The current through the resistor of $40$ $Ω$ is____ mA.

Answer 1

$D_1 : conducting$ and $D_2 : open circuit$

$⇒i=\frac{1−0.6}{60+40}A$

=$\frac{0.4}{100}A$

$⇒ i = 4 \;mA$