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Question

Physics Question on Electric Charge

The curves PP and QQ schematically show the variation of X-ray intensity with wavelength at two different accelerating voltages for a given target material. In the figure, λ1=0.25\lambda_1 = 0.25 Å, λ2=0.5\lambda_2 = 0.5 Å, λ3=1.0\lambda_3 = 1.0 Å, and λ4=2.25\lambda_4 = 2.25 Å. Take Planck's constant as 6.6×10346.6 \times 10^{-34} Js, the speed of light as 3×1083 \times 10^8 m/s, and the elementary charge as 1.6×10191.6 \times 10^{-19} C.

Which of the following statement is/are true?

A

The accelerating potential corresponding to curve P is greater than that of curve Q

B

The accelerating potential applied to obtain curve Q is 24750 V

C

Peaks (II) and (IV) correspond to radiative transitions from L to K shells

D

Peaks (I) and (III) correspond to radiative transitions from N to K shells

Answer

The accelerating potential corresponding to curve P is greater than that of curve Q

Explanation

Solution

The correct Answers are (A) :The accelerating potential corresponding to curve P is greater than that of curve Q(,B):The accelerating potential applied to obtain curve Q is 24750 V,(C):Peaks (II) and (IV) correspond to radiative transitions from L to K shells