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Question

Physics Question on Electricity

The current through a series RL circuit, subjected to a constant emf ϵ\epsilon, obeys Ldidt+iR=ϵL\frac{di}{dt}+iR=\epsilon. Let L=1mH, R=1kΩ\Omega and ϵ\epsilon=1V. The initial condition is i(0)=0. At t=1μs\mu s, the current in mA is

A

1-2e-2

B

1-2e-1

C

1-e-1

D

2-2e-1

Answer

1-e-1

Explanation

Solution

The correct answer is (C) : 1-e-1