Question

The current sensitivity of a moving coil galvanometer is doubled by making the number of turns double. Then its voltage sensitivity will be:

• A. Double
• B. Half
• C. $\frac{1}{4}$times
• D. Remain unchanged

Answer 1

Answer: (D)

Remain unchanged

Answer 2

The voltage sensitivity of a galvanometer depends on the product of current sensitivity and the resistance. Doubling the number of turns increases the current sensitivity, but the overall voltage sensitivity remains unchanged.