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Question

Physics Question on Inductance

The current passing through an inductor coil of 5H is decreasing at the rate of 2A/s, the emf developed across the coil is

A

+10.0V+10.0V

B

10.0V-10.0V

C

+2.5V+2.5V

D

2.5V-2.5V

Answer

+10.0V+10.0V

Explanation

Solution

If on changing current through the coil, the emf induced in the coil ise, then by Faradays 2nd law, we have e=LΔiΔte=-L\frac{\Delta i}{\Delta t} where, ΔiΔt\frac{\Delta i}{\Delta t} is rate of change of current. Given, L=5H, ΔiΔt=2A/sL=5H,\text{ }\frac{\Delta i}{\Delta t}=-2A/s (decreasing) \therefore e=5×(2)=+10Ve=-5\times (-2)=+10V