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Question

Physics Question on Current electricity

The current in the given circuit is

A

4.9 A

B

6.8 A

C

8.3 A

D

2.0 A

Answer

2.0 A

Explanation

Solution

In given circuit RBR_B and RCR_C are in series.
RBC=6+6=12Ω.\therefore \, \, R_{BC} = 6 + 6 = 12\, \Omega.
Now, RAR_A and RBCR_{BC} are in parallel.
Therefore, equivalent resistance of circuit,
Req=12×312+3=3615.\, \, \, \, R_{eq} = \frac{12 \times 3}{12 + 3}= \frac{36}{15}.
Using Ohm's law, I=VReq=4.836/15=2A.I = \frac{V}{R_{eq}}= \frac{4.8}{36/15}= 2\, A.