Question

The current in the following circuit is

• A. 2/3 A
• B. 1 A
• C. 1/8 A
• D. 2/9 A

Answer 1

Answer: (B)

1 A

Answer 2

Applied voltage (V) = 2V and resistances $=3\Omega,3\Omega,3\Omega.$
From the given circuit, we find that two resistances are in series and third resistance is in parallel.
Therefore equivalent resistance for series resistances $=3+3 = 6\Omega.$ Now it is connected parallel with $3\Omega$ resistance. Therefore
$\frac{1}{R}=\frac{1}{3}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2}$ or $R = 2\, \Omega.$
And current flowing in the circuit (I)
$=\frac{V}{R}=\frac{2}{2} = 1\, A.$