The current in the adjoining circuit will be | PHYSICS - KIRCHHOFF'S LAW | SolveeIt

The current in the adjoining circuit will be

$\frac{1}{45}ampere$

$\frac{1}{15}ampere$

$\frac{1}{10}ampere$

$\frac{1}{5}ampere$

Answer

$\frac{1}{10}ampere$

Explanation

$R_{\text{equivalent}} = \frac{(30 + 30)30}{(30 + 30) + 30} = \frac{60 \times 30}{90} = 20\Omega$

$\therefore i = \frac{V}{R} = \frac{2}{20} = \frac{1}{10}ampere$

Question: The current in the adjoining circuit will be <img src="https://cdn.pureessence.tech/canvas_439.png?...