Question

The current in the $1\Omega$ resistor shown in the circuit is

• A. $\frac{2}{3}\,A$
• B. $3\,A$
• C. $6\,A$
• D. $2\,A$

Answer 1

Answer: (D)

$2\,A$

Answer 2

Two $4\Omega$ resistors are in parallel combination. Their equivalent resistance
$=\frac{4\times4}{4+4}=\frac{16}{8}=2\Omega$
$\therefore$ Total resistance of the
network $= 2 + 1 = 3\Omega$
$\therefore$ Current through $1\Omega$ resistor, $i=\frac{6}{3}=2A$