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Question: The current in a coil varies w.r.t. to time t as I = 3t<sup>2</sup> + 2t. If the inductance of coil ...

The current in a coil varies w.r.t. to time t as I = 3t2 + 2t. If the inductance of coil be 10 mH, the value of induced emf at t = 2s will be

A

0.14 V

B

0.12 V

C

0.1 V

D

0.13 V

Answer

0.14 V

Explanation

Solution

e=LdIdt=ddt[3t2+2t]e = - L \frac { d I } { d t } = - \frac { d } { d t } \left[ 3 t ^ { 2 } + 2 t \right] =L[6t+2]=10×103[6t+2]= - L [ 6 t + 2 ] = - 10 \times 10 ^ { - 3 } [ 6 t + 2 ]

e=0.14| e | = 0.14 volt