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Question

Physics Question on Inductance

The current in a coil of inductance 0.2H0.2 \,H changes from 5A5A to 2A2A in 0.5sec0.5\,sec. The magnitude of the average induced emf in the coil is

A

0.6 V

B

1.2 V

C

30 V

D

0.3 V

Answer

1.2 V

Explanation

Solution

Average induced emf, ϵ=Ldl/dt\epsilon= L dl / dt
=0.2((52)/0.5)=2/5×3=1.2V=0.2((5-2) / 0.5)=2 / 5 \times 3=1.2 V