Question

The current $I$ through $10\,\Omega$ resistor in the circuit given below is

• A. $50\,mA$
• B. $20\,mA$
• C. $40\,mA$
• D. $80\,mA$

Answer 1

Answer: (D)

$80\,mA$

Answer 2

Here, diode ${{D}_{2}}$ is reverse biased while ${{D}_{1}}$ is forward biased. So, no current flows across ${{D}_{2}},$ current flows through diode ${{D}_{1}}$
$I=\frac{V}{R}=\frac{2}{10+15}=\frac{2}{25}$
$=0.08A=80\,mA$