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Question

Physics Question on Semiconductor electronics: materials, devices and simple circuits

The current gain of a transistor in common emitter mode is 4949. The change in collector current and emitter current corresponding to the change in base current by 5.0μA,5.0 \,\mu A, will be

A

45μA,250μA45 \,\mu A, 250 \,\mu A

B

240μA,235μA240 \,\mu A, 235 \,\mu A

C

260μA,255μA260 \,\mu A, 255 \,\mu A

D

None of the above

Answer

45μA,250μA45 \,\mu A, 250 \,\mu A

Explanation

Solution

Current gain, β=ΔICΔIB\beta=\frac{\Delta I_{C}}{\Delta I_{B}}
where ΔIC\Delta I_{C} is change in collector current
and ΔIB\Delta I_{B} is change in base current.
ΔIC=βΔIB=49×5=245μA\therefore \Delta I_{C}=\beta \Delta I_{B}=49 \times 5=245\, \mu A
Also, ΔIE=ΔIB+ΔIC \Delta I_{E}=\Delta I_{B}+\Delta I_{C}
=(245+5)μA=250μA=(245+5) \mu A=250 \,\mu A