Question

The current gain of a common base transistor circuit is 0.96. On changing the emitter current by 10.0 mA, the change in the base current will be

• A. 9.6 mA
• B. 0.4 mA
• C. 19.6 mA
• D. 24 mA

Answer 1

Answer: (A)

9.6 mA

Answer 2

Current gain for common base transistor
$\, \, \, \, \, \, \alpha=\bigg(\frac{\Delta I_C}{\Delta I_E}\bigg)_{V_C}$
Given, $\, \, \, \, \, \, \, \, \alpha=0.96 , \Delta I_E =10.0mA$
$\, \, \, \, \, \, \, \, \, \, 0.96=\frac{\Delta I_C}{10.0}$
$\, \, \, \, \, \, \, \, \, \, \Delta I_C =0.96 \times 10.0 =9.6 mA$