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Question

Physics Question on Transistors

The current gain for a transistor working as common-base amplifier is 0.960.96. If the emitter current is 7.2mA7.2\, mA, then base current is

A

0.35 mA

B

0.29 mA

C

0.39 mA

D

0.43 mA

Answer

0.29 mA

Explanation

Solution

α=ICIE\alpha=\frac{I_{C}}{I_{E}} IC=αIE=0.96×7.2=6.91\therefore I_{C}= \alpha I_{E}=0.96\times7.2=6.91 mA Now, IE=IC+IBI_{E} = I_{C} + I_{B} IB=IEIC=7.26.91=0.29\therefore I_{B}=I_{E}-I_{C}=7.2-6.91=0.29 mA