Question

The current flowing through the 3$\Omega$ resistor in the circuit is,

• A. 4.2 A
• B. 3.0 A
• C. 3.5 A
• D. 1.6 A

Answer 1

Answer: (B)

3.0 A

Answer 2

In loop (1) $-12i,-6\left(i-i_{1}\right) +42=0$ In loop(2)
-3i, -35+6$\left(i-i_{1}\right) =0,$ Solving $i_{1}$=-3A
So, current flowing through 3$\Omega$ resistor is 3A.