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Question: The current flowing in a copper voltameter is 3.2 A. The number of copper ions \((Cu^{2 +})\) deposi...

The current flowing in a copper voltameter is 3.2 A. The number of copper ions (Cu2+)(Cu^{2 +}) deposited at the cathode per minute is

A

0.5×10200.5 \times 10^{20}

B

1.5×10201.5 \times 10^{20}

C

3×10203 \times 10^{20}

D

6×10206 \times 10^{20}

Answer

6×10206 \times 10^{20}

Explanation

Solution

Charge supplied per minute = 3.2 × 60 = 192 C

Charge 2e liberates one Cu+2 ion

∴No of Cu+2 ion liberate by 192 C

=1922e=1922×1.6×10−19=6×1020= \frac{192}{2e} = \frac{192}{2 \times 1.6 \times 10^{- 19}} = 6 \times 10^{20}