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Question

Physics Question on AC Voltage

The current and voltage in AC circuit are given by I=5sin(100tπ2)AI=5\sin \left( 100t-\frac{\pi }{2} \right)A and V=200sin(100t)V=200\sin (100t) volt. The power dissipated in the circuit will be

A

20 W

B

40 W

C

1000 W

D

zero

Answer

zero

Explanation

Solution

P=Erms×irms×cosϕP={{E}_{rms}}\times {{i}_{rms}}\times \cos \phi ϕ=π2\phi =\frac{\pi }{2} cosϕ=0\cos \phi =0 P=Erms×irms×(0)=0P={{E}_{rms}}\times {{i}_{rms}}\times (0)=0