Solveeit Logo
Login

Question

Physics Question on Transistors

The current amplification factor α\alpha of a common base transistor and the current amplification factor β\beta of a common emitter transistor are not related by

A

α=β1+β\alpha = \frac{\beta}{1+\beta}

B

β=α1−α\beta= \frac{\alpha}{1-\alpha}

C

1α−1β=1\frac{1}{\alpha} -\frac{1}{\beta} = 1

D

β=α1+α\beta= \frac{\alpha}{1+\alpha}

Answer

β=α1+α\beta= \frac{\alpha}{1+\alpha}

Explanation

Solution

As β=α1−α\beta = \frac{\alpha}{1-\alpha}, so α=β1+β\alpha = \frac{\beta}{1+\beta} and 1α=1β+1\frac{1}{\alpha} = \frac{1}{\beta} +1