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Question: The current amplification factor \(\alpha\) - of a common base transistor and the current amplificat...

The current amplification factor α\alpha - of a common base transistor and the current amplification factor β\beta of a common emitter transistor are not related by

A

α=β1+β\alpha = \frac{\beta}{1 + \beta}

B

β=α1−α\beta = \frac{\alpha}{1 - \alpha}

C

1α−1β=1\frac{1}{\alpha} - \frac{1}{\beta} = 1

D

β=α1+α\beta = \frac{\alpha}{1 + \alpha}

Answer

β=α1+α\beta = \frac{\alpha}{1 + \alpha}

Explanation

Solution

: As β=α1−α,soα=β1+βand1α=1β+1\beta = \frac{\alpha}{1 - \alpha},so\alpha = \frac{\beta}{1 + \beta}and\frac{1}{\alpha} = \frac{1}{\beta} + 1