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Question

Chemistry Question on coordination compounds

The crystal field splitting energy for octahedral (Δ0)(\Delta_0) and tetrahedral (Δt)(\Delta_{t}) complexes is related to :

A

Δt=49Δo\Delta_{t} = \frac{4}{9} \Delta_{o}

B

Δt=12Δo\Delta_{t} = \frac{1}{2} \Delta_{o}

C

Δo=2Δt\Delta_{o} = 2\Delta_{t}

D

Δo=49Δt\Delta_{o} = \frac{4}{9} \Delta_{t}

Answer

Δt=49Δo\Delta_{t} = \frac{4}{9} \Delta_{o}

Explanation

Solution

Since splitting in tetrahedral complex is 23\frac{2}{3} rd of octahedral complex ,so for one legand splitting in OH=Δ06OH =\frac{\Delta_{0}}{6}, then for one legend splitting in tetrahedral is 23(Δ06)\frac{2}{3}\left(\frac{\Delta_{0}}{6}\right), so for 4 legand, Δt=4×23×Δ06\Delta t =4 \times \frac{2}{3} \times \frac{\Delta_{0}}{6} =49Δ0=\frac{4}{9} \Delta_{0}