Question

The critical angle of a certain medium is sin^-1$\left( \frac{3}{5} \right)$the polarizing angle of the medium is:

• A. sin^-1$\left( \frac{4}{5} \right)$
• B. tan^-1$\left( \frac{5}{3} \right)$
• C. tan^-1$\left( \frac{3}{4} \right)$
• D. tan^-1$\left( \frac{4}{3} \right)$

Answer 1

Answer: (B)

tan^-1$\left( \frac{5}{3} \right)$

Answer 2

Here, Critical angle, $i_{c} = \sin^{- 1}\left( \frac{3}{5} \right)\therefore\sin i_{c} = \frac{3}{5}$

As $\mu = \frac{1}{\sin i_{c}} = \frac{5}{3}$

According to Brewster’s law

$\tan i_{p} = \mu$

Where $i_{p}$ is the polarizing angle

$\therefore\tan i_{p} = \frac{5}{3} \Rightarrow i_{p}\tan^{- 1}\left( \frac{5}{3} \right)$