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Question

Physics Question on deccay rate

The count rate of a Geiger Muller counter for the radiation of a radioactive material of half-life of 30 minutes decreases to 5 second1^{-1} after 2 hours. The initial count rate was

A

80 second1^{-1}

B

625second 1^{-1}

C

20second 1^{-1}

D

25 second 1^{-1}

Answer

80 second1^{-1}

Explanation

Solution

Half-life time = 30 minutes; Rate of decrease
(N) = 5 per second and total time = 2 hours = 120 minutes.
Relation for initial and final count rate
NN0=(12)time/halflife=(12)120/30=(12)4=116.\frac{N}{N_0}=\bigg(\frac{1}{2}\bigg)^{time/half-life} =\bigg(\frac{1}{2}\bigg)^{120/30}=\bigg(\frac{1}{2}\bigg)^4=\frac{1}{16}.
Therefore N0_0= 16 x N = 16 x 5 = 80 s1s^{-1}