Question
Quantitative Ability and Data Interpretation Question on Profit and Loss
The cost of running a movie theatre is Rs. 10,000 per day, plus additional Rs. 5000 per show. The theatre has 200 seats. A new movie released on Friday. There were three shows, where the ticket price was Rs. 250 each for the first two shows and Rs. 200 for the late-night show.
For all shows together, total occupancy was 80%. What was the maximum amount of profit possible?
Rs. 1,20,000
Rs. 87,000
Rs. 95,000
Rs. 91,000
Rs. 1,16,000
Rs. 91,000
Solution
Step 1: Calculate total revenue. The theatre has 200 seats, and the total occupancy was 80%, so:
Seats occupied per show = 200 × 0.8 = 160
Revenue from the first two shows (at Rs. 250 per ticket):
Revenue from 2 shows = 160 × 250 × 2 = 80,000 Rs.
Revenue from the late-night show (at Rs. 200 per ticket):
Revenue from 1 show = 160 × 200 = 32,000 Rs.
Total revenue:
80,000 + 32,000 = 1,12,000 Rs.
Step 2: Calculate total cost. Fixed cost for the day:
10,000 Rs.
Cost per show:
5000 × 3 = 15,000 Rs.
Total cost:
10,000 + 15,000 = 25,000 Rs.
Step 3: Calculate profit. Profit:
Profit = Total Revenue − Total Cost
Profit = 1,12,000 − 25,000 = 87,000 Rs.
Answer: Rs. 1,16,000