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Question

Mathematics Question on Percentage

The cost of a machinery is ₹8,00,000. Its scrap value will be one-tenth of its original cost in 15 years. Using the linear method of depreciation, the book value of the machine at the end of the 10th year will be:

A

₹4,80,000

B

₹3,20,000

C

₹3,68,000

D

₹4,32,000

Answer

₹3,20,000

Explanation

Solution

Using the linear method of depreciation, the annual depreciation is calculated as:

Annual Depreciation=Cost of MachineryScrap ValueUseful Life.\text{Annual Depreciation} = \frac{\text{Cost of Machinery} - \text{Scrap Value}}{\text{Useful Life}}.

Here:

Cost of Machinery = 8,00,000, Scrap Value = 8,00,00010=80,000\frac{8,00,000}{10} = 80,000, Useful Life = 15 years.

Annual Depreciation=8,00,00080,00015=7,20,00015=48,000 per year.\text{Annual Depreciation} = \frac{8,00,000 - 80,000}{15} = \frac{7,20,000}{15} = 48,000 \text{ per year}.

The depreciation over 10 years is:

Depreciation for 10 years=48,000×10=4,80,000.\text{Depreciation for 10 years} = 48,000 \times 10 = 4,80,000.

The book value at the end of the 10th year is:

Book Value=Cost of MachineryDepreciation for 10 years=8,00,0004,80,000=3,20,000.\text{Book Value} = \text{Cost of Machinery} - \text{Depreciation for 10 years} = 8,00,000 - 4,80,000 = 3,20,000.

Thus, the book value at the end of the 10th year is Rs. 3,20,000.