Question

The correct set of four quantum numbers for the valence electron of Rubidium (Z = 37) is

• A. n = 5, $\mathcal{l}$ = 0, m = 0, s = + $\frac{1}{2}$
• B. n = 5, $\mathcal{l}$ = 1, m = 0, s = + $\frac{1}{2}$
• C. n = 5, $\mathcal{l}$ = 1, m = 1, s = + $\frac{1}{2}$
• D. n = 6, $\mathcal{l}$ = 0, m = 0, s = +$\frac{1}{2}$

Answer 1

Answer: (A)

n = 5, $\mathcal{l}$ = 0, m = 0, s = + $\frac{1}{2}$

Answer 2

Rb37 : [Kr] 5s2.

$\therefore$ n = 5, $\mathcal{l}$ = 0, m = 0, s = ±$\frac{1}{2}$