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Chemistry Question on Chemical bonding and molecular structure

The correct sequence which shows decreasing order of the ionic radii of the elements is

A

Al3+>Mg2+>Na+>F−>O2−\text{Al}^{3+} > \text{Mg}^{2+} > \text{Na}^+ > \text{F}^- > \text{O}^{2-}

B

Na+>Mg2+>Al3+>O2−>F−\text{Na}^+ > \text{Mg}^{2+} > \text{Al}^{3+} > \text{O}^{2-} > \text{F}^-

C

Na+>F−>Mg2+>O2>Al3+\text{Na}^+ > \text{F}^- > \text{Mg}^{2+} > \text{O}_2 > \text{Al}^{3+}

D

O2−>F−>Na+>Mg2+>Al3+\text{O}^{2-} > \text{F}^- > \text{Na}^+ > \text{Mg}^{2+} > \text{Al}^{3+}

Answer

O2−>F−>Na+>Mg2+>Al3+\text{O}^{2-} > \text{F}^- > \text{Na}^+ > \text{Mg}^{2+} > \text{Al}^{3+}

Explanation

Solution

The correct option is (D): O2−>F−>Na+>Mg2+>Al3+\text{O}^{2-} > \text{F}^- > \text{Na}^+ > \text{Mg}^{2+} > \text{Al}^{3+}