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Question

Chemistry Question on Oxidation Number

The correct sequence of the oxidation state of underlined elements is Na2[Fe(CN)5NO]Na_{2}\left[\frac{Fe}{ }\left(CN\right)_{5}N O\right], K2TaF7K_{2} \frac{Ta}{ }F_{7}, Mg2P2O7Mg_{2}P_{2}O_{7}, Na2S4O6Na_{2} \frac{S_{4}}{ }O_{6}, N3H\frac{N_{3}}{ }H

A

+3+3, +5+5, +5+5, +2.5+2.5, 13-\frac{1}{3}

B

+5+5, +3+3, +5+5, +3+3, +13+\frac{1}{3}

C

+3+3, +3+3, +5+5, +5+5, 13-\frac{1}{3}

D

+5+5, +5+5, +3+3, +2.5+2.5 +13+\frac{1}{3}

Answer

+3+3, +5+5, +5+5, +2.5+2.5, 13-\frac{1}{3}

Explanation

Solution

Na2[Fe(CN)5NO]:+2+x+5(1)+0=0Na_{2}\left[Fe\left(CN\right)_{5}N O\right]: + 2 + x + 5\left(-1\right) + 0 = 0 x=+3\Rightarrow x = +3 K2TaF7:+2+x+(7)=0x=+5K_{2} \frac{Ta}{ }F_{7} : + 2 + x + \left(-7\right) = 0 \Rightarrow x = +5 Mg2P2O7:+4+2x+(14)=0x=+5Mg_{2}P_{2}O_{7} : + 4 + 2x + \left(-14\right) = 0 \Rightarrow x = +5 Na2S4O6:+2+4x+(12)=0Na_{2} \frac{S_{4}}{ }O_{6} : + 2 + 4x + \left(-12\right) = 0 or 4x=10x=+2.54x = 10 \Rightarrow x = + 2.5 N3H:3x+1=0x=13\frac{N_{3}}{ }H : 3x + 1 = 0\quad\Rightarrow\quad x = -\frac{1}{3}