Question

The correct sequence of reactions to be performed to convert benzene into $m$-bromoaniline is

• A. bromination, nitration, reduction
• B. reduction, nitration, bromination
• C. nitration, reduction, bromination
• D. nitration, bromination, reduction

Answer 1

Answer: (D)

nitration, bromination, reduction

Answer 2

Conversion of benzene into $m$ -bromoaniline can be done by successive nitration, bromination and reduction using following reagent

Nitration $\rightarrow$ conc. $HNO _{3} \mid$ conc. $H _{2} SO _{4}$

Bromination $\rightarrow Br _{2} \mid H _{2} O$

Reduction $\rightarrow Sn \mid HCl$

Formation of nitrobenzene in the first step direct incoming electrophile towards meta position on the further step reduction of nitro compound produces m- bromoaniline very easily. Complete sequence of the chemical reaction can be shown as