Solveeit Logo
Login

Question

Question: The correct representation of Nernst's equation is....

The correct representation of Nernst's equation is.

A

Ag++e−→Ag;(Eº=+0.80V)Ag^{+} + e^{-} \rightarrow Ag;(Eº = + 0.80V)

B

Pb2++2Ag→2Ag++PbPb^{2 +} + 2Ag \rightarrow 2Ag^{+} + Pb

C

2Ag+Pb→2Ag++Pb2+2Ag + Pb \rightarrow 2Ag^{+} + Pb^{2 +}

D

None of the above

Answer

Ag++e−→Ag;(Eº=+0.80V)Ag^{+} + e^{-} \rightarrow Ag;(Eº = + 0.80V)

Explanation

Solution

E=Eo−RTnFln⁡1[Mn+]E = E^{o} - \frac{RT}{nF}\ln\frac{1}{\lbrack M^{n +}\rbrack};E=Eo+RTnFln⁡[Mn+]E = E^{o} + \frac{RT}{nF}\ln\lbrack M^{n +}\rbrack

E=Eo+2.303RTnFlog⁡[Mn+]E = E^{o} + \frac{2.303RT}{nF}\log\lbrack M^{n +}\rbrack

Substituting the value of R, T (298K) and F we get

E=Eo+0.0591nlog⁡(Mn+)E = E^{o} + \frac{0.0591}{n}\log(M^{n +}).