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Question: The correct relationship between free energy change in a reaction and the corresponding equilibrium ...

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant, is.

A

ΔG=RTIn⁡Kc\Delta \mathrm { G } = \mathrm { RT } \operatorname { In } \mathrm { K } _ { \mathrm { c } }

B

−ΔG=RTIn⁡Kc- \Delta \mathrm { G } = \mathrm { RT } \operatorname { In } \mathrm { K } _ { \mathrm { c } }

C

ΔGo=RTIn⁡Kc\Delta \mathrm { G } ^ { \mathrm { o } } = \mathrm { RT } \operatorname { In } \mathrm { K } _ { \mathrm { c } }

D

−ΔG∘=RTIn⁡Kc- \Delta \mathrm { G } ^ { \circ } = \mathrm { RT } \operatorname { In } \mathrm { K } _ { \mathrm { c } }

Answer

−ΔG∘=RTIn⁡Kc- \Delta \mathrm { G } ^ { \circ } = \mathrm { RT } \operatorname { In } \mathrm { K } _ { \mathrm { c } }

Explanation

Solution

: −ΔGo=RTln⁡Kc- \Delta \mathrm { G } ^ { \mathrm { o } } = \mathrm { RT } \ln \mathrm { K } _ { \mathrm { c } }