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Question

Physics Question on Transistors

The correct relation for α,β\alpha, \beta for a transistor

A

β=1−αα\beta=\frac{1-\alpha}{\alpha}

B

β=α1−α\beta=\frac{\alpha}{1-\alpha}

C

α=β−1β\alpha=\frac{\beta-1}{\beta}

D

αβ=1.\alpha\beta=1.

Answer

β=α1−α\beta=\frac{\alpha}{1-\alpha}

Explanation

Solution

β=IcIb=IcIe−Ic=Ic/Ie1−(Ic/Ie)=α1−α\beta=\frac{I_c}{Ib}=\frac{I_c}{I_e-I_c}=\frac{I_c/I_e}{1-(I_c/I_e)}=\frac{\alpha}{1-\alpha}