Solveeit Logo

Question

Question: The correct relation between \( {K_{sp}} \) and solubility for the salt, \( K\,Al{(S{O_4})_2} \) is:...

The correct relation between Ksp{K_{sp}} and solubility for the salt, KAl(SO4)2K\,Al{(S{O_4})_2} is:
A. 4s44{s^4}
B. 27s427{s^4}
C. 108s5108{s^5}
D. none of these

Explanation

Solution

Hint : In order to this question, to know the relation between Ksp{K_{sp}} and solubility for the salt, KAl(SO4)2K\,Al{(S{O_4})_2} , we should first write the formula of Ksp{K_{sp}} and then put the given values in the formula from the given compound.

Complete Step By Step Answer:
As we know that,
Ksp=xxyys(x+y){K_{sp}} = {x^x}{y^y}{s^{(x + y)}}
For our question-
KAl(SO4)2K+  +  Al+3  2SO42K\,Al{(S{O_4})_2} \Rightarrow K^+ \;+\; Al^{+3}\; 2SO_4{-2}

| KAl(SO4)2K\,Al{(S{O_4})_2}| K+K^+| Al+3Al^{+3}| 2SO422SO_4{-2}
---|---|---|---|---
Initial| -| -| -| -
At Equilibrium| -| s| s| 2s

Ksp=[K+]  [Al+3]  [SO42]2 {K_{sp}} = [K^+] \; [Al^{+3}] \; [SO_4^{-2}]^2
Ksp=(s)(s)(2s)2=4s4\Rightarrow {K_{sp}} =(s)(s)(2s)^2 = 4s^4
The solubility product is a kind of equilibrium constant and its value depends on temperature. Ksp{K_{sp}} usually increases with an increase in temperature due to increased solubility. Solubility is defined as a property of a substance called solute to get dissolved in a solvent in order to form a solution.
Hence, the correct option is (A).

Note :
Ksp{K_{sp}} usually increases with an increase in temperature due to increased solubility. Solubility is defined as a property of a substance called solute to get dissolved in a solvent in order to form a solution.