Question

The correct order regarding the electronegativity of hybrid orbitals of carbon is

• A. $sp > sp^2 < sp^3$
• B. $sp > sp^2 > sp^3$
• C. $sp < sp^2 > sp^3$
• D. $sp < sp^2 < sp^3$

Answer 1

Answer: (B)

$sp > sp^2 > sp^3$

Answer 2

The correct order regarding the electronegativity of hybrid orbitals of carbon is sp $> sp^2 >sp^3$ because in sp, sp$^2 \, and \, sp^3$ hybrid orbitals s-orbital character is $50\%, 33.3\%$ and $25\%$ respectively and due to higher s-character electron attracting tendency, i.e. electronegativity increases.