Question

The correct order of SN2 / E2 ratio for the % yield of product of the following halide is

(P)

(Q)

(R) $\text{C}\text{H}_{3}\text{ - C}\text{H}_{2}\text{ - I}$

(S)

• A. R > S > Q > P
• B. R > Q > S > P
• C. P > R > S > Q
• D. Q > P > R > S

Answer 1

Answer: (A)

R > S > Q > P

Answer 2

Rate of SN2 reaction : 1⁰ > 2⁰ > 3⁰, as b-branching increases steric crowding increases in transition state so it makes less stable T.S.