Question

The correct order of reduction potentials of the following pairs is

(A)$\frac{Cl_2}{Cl^–}$

(B)$\frac{I_2}{I^–}$

(C) $\frac{Ag^+}{Ag}$

(D) $\frac{Na^+}{Na}$

(E) $\frac{Li^+}{ Li}$

Choose the correct answer from the options given below:

• A. A > C > B > D > E
• B. A > B > C > D > E
• C. A > C > B > E > D
• D. A > B > C > E > D

Answer 1

Answer: (A)

A > C > B > D > E

Answer 2

The correct option is (A): A > C > B > D > E.

-	Standard Reduction Potential
(A) Cl2/Cl	1.36 V
(B) I2/I–	0.54 V
(C) Ag+/Ag	0.80 V
(D) Na+/Na	–2.71 V
(E) Li+/ Li	–3.05 V

Hence, correct order is A > C > B > D > E