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Chemistry Question on Molecular Orbital Theory

The correct order of N−ON - O bond lengths in NO,NO2−,NO3−NO, NO_2^-, NO_3^- and N2O4N_2O_4 is

A

N2O4>NO2−>NO3−>NON_2O_4 > NO_2^- > NO_3^- > NO

B

NO>NO3−>N2O4>NO2− NO > NO_3^- > N_2O_4 > NO_2^-

C

NO3−>NO2−>N2O4>NO NO_3^- > NO_2^- > N_2O_4 > NO

D

NO>N2O4>NO2−>NO3−NO > N_2O_4 > NO_2^- > NO_3^-

Answer

NO3−>NO2−>N2O4>NO NO_3^- > NO_2^- > N_2O_4 > NO

Explanation

Solution

As the bond order increases, bond length decreases and bond order is highest for NO, i.e. 2.5 and least for NO3−NO_3^- , i.e. 1.33. So, the order of bond length is
NO3−>NO2>N2O4>NONO_3^- > NO_2 > N_2O_4 > NO