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Question: The correct order of magnetic moments (spin only values in B.M.) among is....

The correct order of magnetic moments (spin only values in B.M.) among is.

A

[Fe(CN)6]4−>[MnCl4]2−>[CoCl4]2−\lbrack Fe(CN)_{6}\rbrack^{4 -} > \lbrack MnCl_{4}\rbrack^{2 -} > \lbrack CoCl_{4}\rbrack^{2 -}

B

[MnCl4]2−>[Fe(CN)6]4−>[CoCl4]2−\lbrack MnCl_{4}\rbrack^{2 -} > \lbrack Fe(CN)_{6}\rbrack^{4 -} > \lbrack CoCl_{4}\rbrack^{2 -}

C

[MnCl4]2−>[CoCl4]2−>[Fe(CN)6]4−\lbrack MnCl_{4}\rbrack^{2 -} > \lbrack CoCl_{4}\rbrack^{2 -} > \lbrack Fe(CN)_{6}\rbrack^{4 -}

D

[Fe(CN)6]4−>[CoCl4]2−>[MnCl4]2−\lbrack Fe(CN)_{6}\rbrack^{4 -} > \lbrack CoCl_{4}\rbrack^{2 -} > \lbrack MnCl_{4}\rbrack^{2 -}

Atomic nos Mn=25,Fe=26,Co=27Mn = 25,Fe = 26,Co = 27

Answer

[MnCl4]2−>[CoCl4]2−>[Fe(CN)6]4−\lbrack MnCl_{4}\rbrack^{2 -} > \lbrack CoCl_{4}\rbrack^{2 -} > \lbrack Fe(CN)_{6}\rbrack^{4 -}

Explanation

Solution

Magnetic moment =n+2= \sqrt{n + 2}

Where, n = number of unpaired electron i.e., greater the number of unpaired electron greater will be the paramagnetic character.